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20=-4.9x^2+26x+1
We move all terms to the left:
20-(-4.9x^2+26x+1)=0
We get rid of parentheses
4.9x^2-26x-1+20=0
We add all the numbers together, and all the variables
4.9x^2-26x+19=0
a = 4.9; b = -26; c = +19;
Δ = b2-4ac
Δ = -262-4·4.9·19
Δ = 303.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-\sqrt{303.6}}{2*4.9}=\frac{26-\sqrt{303.6}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+\sqrt{303.6}}{2*4.9}=\frac{26+\sqrt{303.6}}{9.8} $
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